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211434220023 = 31337310947129
BaseRepresentation
bin1100010011101001110…
…1100010100111110111
3202012202012210020121220
43010322131202213313
511431004130020043
6241044225041423
721163352134305
oct3047235424767
9665665706556
10211434220023
118173a117a14
1234b88a86273
1316c271a9b40
14a33a903275
1557771d6483
hex313a7629f7

211434220023 has 32 divisors (see below), whose sum is σ = 311910110400. Its totient is φ = 126553383936.

The previous prime is 211434220021. The next prime is 211434220027. The reversal of 211434220023 is 320022434112.

It is a happy number.

It is not a de Polignac number, because 211434220023 - 21 = 211434220021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211434219975 and 211434220002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211434220021) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4462723 + ... + 4509851.

It is an arithmetic number, because the mean of its divisors is an integer number (9747190950).

Almost surely, 2211434220023 is an apocalyptic number.

211434220023 is a deficient number, since it is larger than the sum of its proper divisors (100475890377).

211434220023 is a wasteful number, since it uses less digits than its factorization.

211434220023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50291.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 211434220023 its reverse (320022434112), we get a palindrome (531456654135).

The spelling of 211434220023 in words is "two hundred eleven billion, four hundred thirty-four million, two hundred twenty thousand, twenty-three".

Divisors: 1 3 13 37 39 111 481 1443 3109 9327 40417 47129 115033 121251 141387 345099 612677 1495429 1743773 1838031 4486287 5231319 22669049 68007147 146524061 439572183 1904812793 5421390257 5714438379 16264170771 70478073341 211434220023