Base | Representation |
---|---|
bin | 11110110001001110011… |
… | …110001011001000110111 |
3 | 21111010201222201200012122 |
4 | 132301032132023020313 |
5 | 234120333223124143 |
6 | 4255205512510155 |
7 | 305522543133551 |
oct | 36611636131067 |
9 | 7433658650178 |
10 | 2114440442423 |
11 | 745802563021 |
12 | 2a19619ab35b |
13 | 1245109b42aa |
14 | 744a76b84d1 |
15 | 3a004d4bc68 |
hex | 1ec4e78b237 |
2114440442423 has 2 divisors, whose sum is σ = 2114440442424. Its totient is φ = 2114440442422.
The previous prime is 2114440442377. The next prime is 2114440442437. The reversal of 2114440442423 is 3242440444112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2114440442423 - 226 = 2114373333559 is a prime.
It is a super-2 number, since 2×21144404424232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2114440444423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057220221211 + 1057220221212.
It is an arithmetic number, because the mean of its divisors is an integer number (1057220221212).
Almost surely, 22114440442423 is an apocalyptic number.
2114440442423 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114440442423 is an equidigital number, since it uses as much as digits as its factorization.
2114440442423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 98304, while the sum is 35.
Adding to 2114440442423 its reverse (3242440444112), we get a palindrome (5356880886535).
The spelling of 2114440442423 in words is "two trillion, one hundred fourteen billion, four hundred forty million, four hundred forty-two thousand, four hundred twenty-three".
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