Base | Representation |
---|---|
bin | 11110110001010100011… |
… | …001100000000111000001 |
3 | 21111010222220211200011002 |
4 | 132301110121200013001 |
5 | 234121034202142042 |
6 | 4255223424101345 |
7 | 305525161266623 |
oct | 36612431400701 |
9 | 7433886750132 |
10 | 2114539880897 |
11 | 745853700684 |
12 | 2a198b164855 |
13 | 12452848c322 |
14 | 744b69a0c13 |
15 | 3a00d940132 |
hex | 1ec546601c1 |
2114539880897 has 2 divisors, whose sum is σ = 2114539880898. Its totient is φ = 2114539880896.
The previous prime is 2114539880891. The next prime is 2114539880899. The reversal of 2114539880897 is 7980889354112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2016147247921 + 98392632976 = 1419911^2 + 313676^2 .
It is a cyclic number.
It is not a de Polignac number, because 2114539880897 - 216 = 2114539815361 is a prime.
Together with 2114539880899, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2114539880891) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057269940448 + 1057269940449.
It is an arithmetic number, because the mean of its divisors is an integer number (1057269940449).
Almost surely, 22114539880897 is an apocalyptic number.
It is an amenable number.
2114539880897 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114539880897 is an equidigital number, since it uses as much as digits as its factorization.
2114539880897 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34836480, while the sum is 65.
The spelling of 2114539880897 in words is "two trillion, one hundred fourteen billion, five hundred thirty-nine million, eight hundred eighty thousand, eight hundred ninety-seven".
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