Base | Representation |
---|---|
bin | 1100010011101110100… |
… | …0111100110011111101 |
3 | 202012210120222120022122 |
4 | 3010323220330303331 |
5 | 11431024210104333 |
6 | 241050212452325 |
7 | 21164012146205 |
oct | 3047350746375 |
9 | 665716876278 |
10 | 211453988093 |
11 | 8174a299a67 |
12 | 34b9361a0a5 |
13 | 16c2b30b81a |
14 | a33d3ab405 |
15 | 5778cdd798 |
hex | 313ba3ccfd |
211453988093 has 4 divisors (see below), whose sum is σ = 211459867008. Its totient is φ = 211448109180.
The previous prime is 211453988051. The next prime is 211453988177. The reversal of 211453988093 is 390889354112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 211453988093 - 232 = 207159020797 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211453988023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2885171 + ... + 2957552.
It is an arithmetic number, because the mean of its divisors is an integer number (52864966752).
Almost surely, 2211453988093 is an apocalyptic number.
It is an amenable number.
211453988093 is a deficient number, since it is larger than the sum of its proper divisors (5878915).
211453988093 is an equidigital number, since it uses as much as digits as its factorization.
211453988093 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5878914.
The product of its (nonzero) digits is 1866240, while the sum is 53.
The spelling of 211453988093 in words is "two hundred eleven billion, four hundred fifty-three million, nine hundred eighty-eight thousand, ninety-three".
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