Base | Representation |
---|---|
bin | 1001100111100011000000… |
… | …11011000001001110011111 |
3 | 2202212220221102100000122202 |
4 | 10303301200123001032133 |
5 | 10233010233341124101 |
6 | 112552105343002115 |
7 | 4312016424242666 |
oct | 463614033011637 |
9 | 82786842300582 |
10 | 21150036661151 |
11 | 6814753351152 |
12 | 245702859933b |
13 | ba55945c68c8 |
14 | 53194ac79ddd |
15 | 26a26351e36b |
hex | 133c606c139f |
21150036661151 has 4 divisors (see below), whose sum is σ = 21665891213904. Its totient is φ = 20634182108400.
The previous prime is 21150036661141. The next prime is 21150036661153. The reversal of 21150036661151 is 15116663005112.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21150036661151 - 222 = 21150032466847 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21150036661153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 257927276315 + ... + 257927276396.
It is an arithmetic number, because the mean of its divisors is an integer number (5416472803476).
Almost surely, 221150036661151 is an apocalyptic number.
21150036661151 is a deficient number, since it is larger than the sum of its proper divisors (515854552753).
21150036661151 is an equidigital number, since it uses as much as digits as its factorization.
21150036661151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 515854552752.
The product of its (nonzero) digits is 32400, while the sum is 38.
Adding to 21150036661151 its reverse (15116663005112), we get a palindrome (36266699666263).
The spelling of 21150036661151 in words is "twenty-one trillion, one hundred fifty billion, thirty-six million, six hundred sixty-one thousand, one hundred fifty-one".
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