Base | Representation |
---|---|
bin | 11110110001110110011… |
… | …000110001011100011111 |
3 | 21111012110122211120102111 |
4 | 132301312120301130133 |
5 | 234123221142140403 |
6 | 4255400154134451 |
7 | 305545254224206 |
oct | 36616630613437 |
9 | 7435418746374 |
10 | 2115110115103 |
11 | 746016579017 |
12 | 2a1b0a121427 |
13 | 1245b966570b |
14 | 7452c5da23d |
15 | 3a043a2d56d |
hex | 1ec7663171f |
2115110115103 has 2 divisors, whose sum is σ = 2115110115104. Its totient is φ = 2115110115102.
The previous prime is 2115110114947. The next prime is 2115110115121. The reversal of 2115110115103 is 3015110115112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2115110115103 - 29 = 2115110114591 is a prime.
It is a super-2 number, since 2×21151101151032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2115110116103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057555057551 + 1057555057552.
It is an arithmetic number, because the mean of its divisors is an integer number (1057555057552).
Almost surely, 22115110115103 is an apocalyptic number.
2115110115103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2115110115103 is an equidigital number, since it uses as much as digits as its factorization.
2115110115103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 150, while the sum is 22.
Subtracting 2115110115103 from its reverse (3015110115112), we obtain a palindrome (900000000009).
The spelling of 2115110115103 in words is "two trillion, one hundred fifteen billion, one hundred ten million, one hundred fifteen thousand, one hundred three".
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