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2115110115113 = 53126593152519
BaseRepresentation
bin11110110001110110011…
…000110001011100101001
321111012110122211120102212
4132301312120301130221
5234123221142140423
64255400154134505
7305545254224222
oct36616630613451
97435418746385
102115110115113
11746016579026
122a1b0a121435
131245b9665718
147452c5da249
153a043a2d578
hex1ec76631729

2115110115113 has 8 divisors (see below), whose sum is σ = 2155188772800. Its totient is φ = 2075037787888.

The previous prime is 2115110115103. The next prime is 2115110115121. The reversal of 2115110115113 is 3115110115112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2115110115113 - 226 = 2115043006249 is a prime.

It is a super-2 number, since 2×21151101151132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2115110115103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 905333 + ... + 2247186.

It is an arithmetic number, because the mean of its divisors is an integer number (269398596600).

Almost surely, 22115110115113 is an apocalyptic number.

It is an amenable number.

2115110115113 is a deficient number, since it is larger than the sum of its proper divisors (40078657687).

2115110115113 is a wasteful number, since it uses less digits than its factorization.

2115110115113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3165231.

The product of its (nonzero) digits is 150, while the sum is 23.

Subtracting 2115110115113 from its reverse (3115110115112), we obtain a palindrome (999999999999).

The spelling of 2115110115113 in words is "two trillion, one hundred fifteen billion, one hundred ten million, one hundred fifteen thousand, one hundred thirteen".

Divisors: 1 53 12659 670927 3152519 167083507 39907738021 2115110115113