Base | Representation |
---|---|
bin | 1001100111101100100001… |
… | …10010100111011110011111 |
3 | 2202220102010022001001101212 |
4 | 10303312100302213132133 |
5 | 10233101213114331144 |
6 | 112554312200055035 |
7 | 4312260111365312 |
oct | 463662062473637 |
9 | 82812108031355 |
10 | 21155143120799 |
11 | 6816933861936 |
12 | 245801276447b |
13 | ba5bc951b26c |
14 | 531cb3130979 |
15 | 26a4619a449e |
hex | 133d90ca779f |
21155143120799 has 2 divisors, whose sum is σ = 21155143120800. Its totient is φ = 21155143120798.
The previous prime is 21155143120753. The next prime is 21155143120801. The reversal of 21155143120799 is 99702134155112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21155143120799 - 236 = 21086423644063 is a prime.
It is a super-2 number, since 2×211551431207992 (a number of 27 digits) contains 22 as substring.
Together with 21155143120801, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21155143120999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10577571560399 + 10577571560400.
It is an arithmetic number, because the mean of its divisors is an integer number (10577571560400).
Almost surely, 221155143120799 is an apocalyptic number.
21155143120799 is a deficient number, since it is larger than the sum of its proper divisors (1).
21155143120799 is an equidigital number, since it uses as much as digits as its factorization.
21155143120799 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 680400, while the sum is 50.
The spelling of 21155143120799 in words is "twenty-one trillion, one hundred fifty-five billion, one hundred forty-three million, one hundred twenty thousand, seven hundred ninety-nine".
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