Base | Representation |
---|---|
bin | 1100010100010110101… |
… | …0010111000101111101 |
3 | 202020020022101001201100 |
4 | 3011011222113011331 |
5 | 11431400231130140 |
6 | 241115020403313 |
7 | 21201123266034 |
oct | 3050552270575 |
9 | 666208331640 |
10 | 211622130045 |
11 | 818261a2557 |
12 | 3501b9a6539 |
13 | 16c570c01c1 |
14 | a35785971b |
15 | 5788953530 |
hex | 3145a9717d |
211622130045 has 24 divisors (see below), whose sum is σ = 368413507800. Its totient is φ = 112372269696.
The previous prime is 211622130037. The next prime is 211622130101. The reversal of 211622130045 is 540031226112.
211622130045 is a `hidden beast` number, since 2 + 1 + 1 + 622 + 1 + 30 + 0 + 4 + 5 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 117113843961 + 94508286084 = 342219^2 + 307422^2 .
It is not a de Polignac number, because 211622130045 - 23 = 211622130037 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10257630 + ... + 10278239.
It is an arithmetic number, because the mean of its divisors is an integer number (15350562825).
Almost surely, 2211622130045 is an apocalyptic number.
It is an amenable number.
211622130045 is a deficient number, since it is larger than the sum of its proper divisors (156791377755).
211622130045 is a wasteful number, since it uses less digits than its factorization.
211622130045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20536109 (or 20536106 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 211622130045 its reverse (540031226112), we get a palindrome (751653356157).
The spelling of 211622130045 in words is "two hundred eleven billion, six hundred twenty-two million, one hundred thirty thousand, forty-five".
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