2116251412151 has 2 divisors, whose sum is σ = 2116251412152. Its totient is φ = 2116251412150.

The previous prime is 2116251412129. The next prime is 2116251412153. The reversal of 2116251412151 is 1512141526112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2116251412151 - 2⁶ = 2116251412087 is a prime.

It is a super-3 number, since 3×2116251412151³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 2116251412153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2116251412153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1058125706075 + 1058125706076.

It is an arithmetic number, because the mean of its divisors is an integer number (1058125706076).

Almost surely, 2^{2116251412151} is an apocalyptic number.

2116251412151 is a deficient number, since it is larger than the sum of its proper divisors (1).

2116251412151 is an equidigital number, since it uses as much as digits as its factorization.

2116251412151 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4800, while the sum is 32.

Adding to 2116251412151 its reverse (1512141526112), we get a palindrome (3628392938263).

The spelling of 2116251412151 in words is "two trillion, one hundred sixteen billion, two hundred fifty-one million, four hundred twelve thousand, one hundred fifty-one".