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21200012116133 is a prime number
BaseRepresentation
bin1001101001000000000110…
…01100010000000010100101
32210001200221021222011211212
410310200003030100002211
510234320111100204013
6113031052350241205
74315436030506634
oct464400314200245
983050837864755
1021200012116133
11683396917a164
1224648551b6205
13baa1ca251546
1453412c21b51b
1526b6dab666a8
hex1348033100a5

21200012116133 has 2 divisors, whose sum is σ = 21200012116134. Its totient is φ = 21200012116132.

The previous prime is 21200012116123. The next prime is 21200012116177. The reversal of 21200012116133 is 33161121000212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12414615339844 + 8785396776289 = 3523438^2 + 2964017^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21200012116133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21200012116099 and 21200012116108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21200012116123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10600006058066 + 10600006058067.

It is an arithmetic number, because the mean of its divisors is an integer number (10600006058067).

Almost surely, 221200012116133 is an apocalyptic number.

It is an amenable number.

21200012116133 is a deficient number, since it is larger than the sum of its proper divisors (1).

21200012116133 is an equidigital number, since it uses as much as digits as its factorization.

21200012116133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 21200012116133 its reverse (33161121000212), we get a palindrome (54361133116345).

The spelling of 21200012116133 in words is "twenty-one trillion, two hundred billion, twelve million, one hundred sixteen thousand, one hundred thirty-three".