Base | Representation |
---|---|
bin | 1001101001000010001001… |
… | …01000110000111111111111 |
3 | 2210001210202211001001120001 |
4 | 10310201010220300333333 |
5 | 10234324333142011312 |
6 | 113031353332135131 |
7 | 4315505162346556 |
oct | 464410450607777 |
9 | 83053684031501 |
10 | 21201110110207 |
11 | 6834381a44385 |
12 | 2464b00a674a7 |
13 | baa34387c191 |
14 | 5341d3d96d9d |
15 | 26b752253057 |
hex | 134844a30fff |
21201110110207 has 2 divisors, whose sum is σ = 21201110110208. Its totient is φ = 21201110110206.
The previous prime is 21201110110121. The next prime is 21201110110211. The reversal of 21201110110207 is 70201101110212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21201110110207 - 211 = 21201110108159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21201110110247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10600555055103 + 10600555055104.
It is an arithmetic number, because the mean of its divisors is an integer number (10600555055104).
Almost surely, 221201110110207 is an apocalyptic number.
21201110110207 is a deficient number, since it is larger than the sum of its proper divisors (1).
21201110110207 is an equidigital number, since it uses as much as digits as its factorization.
21201110110207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 21201110110207 its reverse (70201101110212), we get a palindrome (91402211220419).
The spelling of 21201110110207 in words is "twenty-one trillion, two hundred one billion, one hundred ten million, one hundred ten thousand, two hundred seven".
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