Base | Representation |
---|---|
bin | 11110110110100000011… |
… | …101101011010100110111 |
3 | 21111200101011220102002202 |
4 | 132312200131223110313 |
5 | 234213441404324002 |
6 | 4301544320455115 |
7 | 306113220153044 |
oct | 36664035532467 |
9 | 7450334812082 |
10 | 2120111011127 |
11 | 74815243823a |
12 | 2a2a84a7a49b |
13 | 124c057490a5 |
14 | 748848521cb |
15 | 3a237ab0502 |
hex | 1eda076b537 |
2120111011127 has 2 divisors, whose sum is σ = 2120111011128. Its totient is φ = 2120111011126.
The previous prime is 2120111011079. The next prime is 2120111011133. The reversal of 2120111011127 is 7211101110212.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2120111011127 - 26 = 2120111011063 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2120111011099 and 2120111011108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2120111011177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060055505563 + 1060055505564.
It is an arithmetic number, because the mean of its divisors is an integer number (1060055505564).
Almost surely, 22120111011127 is an apocalyptic number.
2120111011127 is a deficient number, since it is larger than the sum of its proper divisors (1).
2120111011127 is an equidigital number, since it uses as much as digits as its factorization.
2120111011127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 2120111011127 its reverse (7211101110212), we get a palindrome (9331212121339).
The spelling of 2120111011127 in words is "two trillion, one hundred twenty billion, one hundred eleven million, eleven thousand, one hundred twenty-seven".
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