Base | Representation |
---|---|
bin | 110000001101001010101111… |
… | …000001010001100100001111 |
3 | 1000210200001201220220212020121 |
4 | 300031022233001101210033 |
5 | 210242042224133341142 |
6 | 2030524321004325411 |
7 | 62441203666014565 |
oct | 6015125701214417 |
9 | 1023601656825217 |
10 | 212011112012047 |
11 | 6160a453681287 |
12 | 1b941210543867 |
13 | 913b73cb6420a |
14 | 3a4d56d30da35 |
15 | 1979d677c7c67 |
hex | c0d2af05190f |
212011112012047 has 2 divisors, whose sum is σ = 212011112012048. Its totient is φ = 212011112012046.
The previous prime is 212011112012009. The next prime is 212011112012059. The reversal of 212011112012047 is 740210211110212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212011112012047 - 223 = 212011103623439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212011112012087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106005556006023 + 106005556006024.
It is an arithmetic number, because the mean of its divisors is an integer number (106005556006024).
Almost surely, 2212011112012047 is an apocalyptic number.
212011112012047 is a deficient number, since it is larger than the sum of its proper divisors (1).
212011112012047 is an equidigital number, since it uses as much as digits as its factorization.
212011112012047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 25.
Adding to 212011112012047 its reverse (740210211110212), we get a palindrome (952221323122259).
The spelling of 212011112012047 in words is "two hundred twelve trillion, eleven billion, one hundred twelve million, twelve thousand, forty-seven".
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