Base | Representation |
---|---|
bin | 1100010101110011011… |
… | …1000000111011111011 |
3 | 202021020102201010021002 |
4 | 3011130313000323323 |
5 | 11433144344320011 |
6 | 241221402235215 |
7 | 21213560340536 |
oct | 3053467007373 |
9 | 667212633232 |
10 | 212011323131 |
11 | 81a05957033 |
12 | 3510a1b5b0b |
13 | 16cb991987a |
14 | a393409a1d |
15 | 57acbcec3b |
hex | 315cdc0efb |
212011323131 has 2 divisors, whose sum is σ = 212011323132. Its totient is φ = 212011323130.
The previous prime is 212011323113. The next prime is 212011323133. The reversal of 212011323131 is 131323110212.
It is a happy number.
Together with previous prime (212011323113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212011323131 is a prime.
It is a super-2 number, since 2×2120113231312 (a number of 23 digits) contains 22 as substring.
Together with 212011323133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (212011323133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106005661565 + 106005661566.
It is an arithmetic number, because the mean of its divisors is an integer number (106005661566).
Almost surely, 2212011323131 is an apocalyptic number.
212011323131 is a deficient number, since it is larger than the sum of its proper divisors (1).
212011323131 is an equidigital number, since it uses as much as digits as its factorization.
212011323131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 212011323131 its reverse (131323110212), we get a palindrome (343334433343).
The spelling of 212011323131 in words is "two hundred twelve billion, eleven million, three hundred twenty-three thousand, one hundred thirty-one".
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