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212013043103 = 552073840329
BaseRepresentation
bin1100010101110011110…
…1100100110110011111
3202021020112221111121202
43011130331210312133
511433200314334403
6241221503150115
721213611063201
oct3053475446637
9667215844552
10212013043103
1181a069212a4
123510a8a533b
1316cba09c6c4
14a393736771
1557ace1e688
hex315cf64d9f

212013043103 has 4 divisors (see below), whose sum is σ = 212016938640. Its totient is φ = 212009147568.

The previous prime is 212013043097. The next prime is 212013043111. The reversal of 212013043103 is 301340310212.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 212013043103 - 220 = 212011994527 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (212013043703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1864958 + ... + 1975371.

It is an arithmetic number, because the mean of its divisors is an integer number (53004234660).

Almost surely, 2212013043103 is an apocalyptic number.

212013043103 is a deficient number, since it is larger than the sum of its proper divisors (3895537).

212013043103 is an equidigital number, since it uses as much as digits as its factorization.

212013043103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3895536.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 212013043103 its reverse (301340310212), we get a palindrome (513353353315).

The spelling of 212013043103 in words is "two hundred twelve billion, thirteen million, forty-three thousand, one hundred three".

Divisors: 1 55207 3840329 212013043103