Base | Representation |
---|---|
bin | 1100010101110100000… |
… | …1101100010110100111 |
3 | 202021020121222100010222 |
4 | 3011131001230112213 |
5 | 11433201103404112 |
6 | 241221542234555 |
7 | 21213623206643 |
oct | 3053501542647 |
9 | 667217870128 |
10 | 212014122407 |
11 | 81a0749918a |
12 | 3510b125a5b |
13 | 16cba389a49 |
14 | a393937c23 |
15 | 57ad084372 |
hex | 315d06c5a7 |
212014122407 has 2 divisors, whose sum is σ = 212014122408. Its totient is φ = 212014122406.
The previous prime is 212014122317. The next prime is 212014122457. The reversal of 212014122407 is 704221410212.
It is a happy number.
212014122407 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212014122407 - 210 = 212014121383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212014122457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106007061203 + 106007061204.
It is an arithmetic number, because the mean of its divisors is an integer number (106007061204).
Almost surely, 2212014122407 is an apocalyptic number.
212014122407 is a deficient number, since it is larger than the sum of its proper divisors (1).
212014122407 is an equidigital number, since it uses as much as digits as its factorization.
212014122407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1792, while the sum is 26.
Adding to 212014122407 its reverse (704221410212), we get a palindrome (916235532619).
The spelling of 212014122407 in words is "two hundred twelve billion, fourteen million, one hundred twenty-two thousand, four hundred seven".
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