Base | Representation |
---|---|
bin | 1001101001000100011000… |
… | …00010110010011100000011 |
3 | 2210001220212022021222001112 |
4 | 10310202030002302130003 |
5 | 10234334311334123204 |
6 | 113032112245353535 |
7 | 4315546650252533 |
oct | 464421402623403 |
9 | 83056768258045 |
10 | 21202308114179 |
11 | 6834937207505 |
12 | 24651961088ab |
13 | baa4a4b24c7a |
14 | 5342a91274c3 |
15 | 26b7c24e726e |
hex | 13488c0b2703 |
21202308114179 has 2 divisors, whose sum is σ = 21202308114180. Its totient is φ = 21202308114178.
The previous prime is 21202308114173. The next prime is 21202308114181. The reversal of 21202308114179 is 97141180320212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21202308114179 - 212 = 21202308110083 is a prime.
Together with 21202308114181, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (21202308114173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10601154057089 + 10601154057090.
It is an arithmetic number, because the mean of its divisors is an integer number (10601154057090).
Almost surely, 221202308114179 is an apocalyptic number.
21202308114179 is a deficient number, since it is larger than the sum of its proper divisors (1).
21202308114179 is an equidigital number, since it uses as much as digits as its factorization.
21202308114179 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 41.
The spelling of 21202308114179 in words is "twenty-one trillion, two hundred two billion, three hundred eight million, one hundred fourteen thousand, one hundred seventy-nine".
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