Search a number
-
+
2121011320037 is a prime number
BaseRepresentation
bin11110110111010110001…
…000000101010011100101
321111202200220222211202012
4132313112020011103211
5234222312344220122
64302213521324005
7306144431516261
oct36672610052345
97452626884665
102121011320037
11748574660695
122a3096496605
1312501a12025c
147492c24d0a1
153a28bb4d7e2
hex1edd62054e5

2121011320037 has 2 divisors, whose sum is σ = 2121011320038. Its totient is φ = 2121011320036.

The previous prime is 2121011319967. The next prime is 2121011320067. The reversal of 2121011320037 is 7300231101212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1830936440641 + 290074879396 = 1353121^2 + 538586^2 .

It is a cyclic number.

It is not a de Polignac number, because 2121011320037 - 28 = 2121011319781 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2121011319994 and 2121011320021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2121011320067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060505660018 + 1060505660019.

It is an arithmetic number, because the mean of its divisors is an integer number (1060505660019).

Almost surely, 22121011320037 is an apocalyptic number.

It is an amenable number.

2121011320037 is a deficient number, since it is larger than the sum of its proper divisors (1).

2121011320037 is an equidigital number, since it uses as much as digits as its factorization.

2121011320037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 2121011320037 its reverse (7300231101212), we get a palindrome (9421242421249).

The spelling of 2121011320037 in words is "two trillion, one hundred twenty-one billion, eleven million, three hundred twenty thousand, thirty-seven".