Base | Representation |
---|---|
bin | 1100010110001000110… |
… | …1110111100010001011 |
3 | 202021110200211100011102 |
4 | 3011202031313202023 |
5 | 11433340401400021 |
6 | 241234332452015 |
7 | 21216031311341 |
oct | 3054215674213 |
9 | 667420740142 |
10 | 212101200011 |
11 | 81a51663948 |
12 | 3513431a00b |
13 | 1700242775c |
14 | a3a1323991 |
15 | 57b5a3500b |
hex | 316237788b |
212101200011 has 4 divisors (see below), whose sum is σ = 212169424800. Its totient is φ = 212032975224.
The previous prime is 212101200001. The next prime is 212101200019. The reversal of 212101200011 is 110002101212.
212101200011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212101200011 is a prime.
It is a super-3 number, since 3×2121012000113 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 212101199965 and 212101200001.
It is not an unprimeable number, because it can be changed into a prime (212101200019) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34107731 + ... + 34113948.
It is an arithmetic number, because the mean of its divisors is an integer number (53042356200).
Almost surely, 2212101200011 is an apocalyptic number.
212101200011 is a deficient number, since it is larger than the sum of its proper divisors (68224789).
212101200011 is an equidigital number, since it uses as much as digits as its factorization.
212101200011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 68224788.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 212101200011 its reverse (110002101212), we get a palindrome (322103301223).
It can be divided in two parts, 21210 and 1200011, that added together give a palindrome (1221221).
The spelling of 212101200011 in words is "two hundred twelve billion, one hundred one million, two hundred thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •