212111111213 has 4 divisors (see below), whose sum is σ = 224588235420. Its totient is φ = 199633987008.

The previous prime is 212111111209. The next prime is 212111111237. The reversal of 212111111213 is 312111111212.

212111111213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 190795987204 + 21315124009 = 436802^2 + 145997^2 .

It is a cyclic number.

It is not a de Polignac number, because 212111111213 - 2² = 212111111209 is a prime.

It is a super-2 number, since 2×212111111213² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 12477124189 = 212111111213 / (2 + 1 + 2 + 1 + 1 + 1 + 1 + 1 + 1 + 2 + 1 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 212111111191 and 212111111200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (212111111203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6238562078 + ... + 6238562111.

It is an arithmetic number, because the mean of its divisors is an integer number (56147058855).

Almost surely, 2^212111111213 is an apocalyptic number.

It is an amenable number.

212111111213 is a deficient number, since it is larger than the sum of its proper divisors (12477124207).

212111111213 is a wasteful number, since it uses less digits than its factorization.

212111111213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12477124206.

The product of its digits is 24, while the sum is 17.

Adding to 212111111213 its reverse (312111111212), we get a palindrome (524222222425).

Subtracting 212111111213 from its reverse (312111111212), we obtain a palindrome (99999999999).

The spelling of 212111111213 in words is "two hundred twelve billion, one hundred eleven million, one hundred eleven thousand, two hundred thirteen".