Base | Representation |
---|---|
bin | 110000001110101000110011… |
… | …101000110010100100011111 |
3 | 1000211000201110102112211102111 |
4 | 300032220303220302210133 |
5 | 210300221111012224132 |
6 | 2031042544022134451 |
7 | 62451411046026562 |
oct | 6016506350624437 |
9 | 1024021412484374 |
10 | 212112121211167 |
11 | 61649277743641 |
12 | 1b958900281427 |
13 | 9148119781ca8 |
14 | 3a543d23d44d9 |
15 | 197c7ca40e647 |
hex | c0ea33a3291f |
212112121211167 has 2 divisors, whose sum is σ = 212112121211168. Its totient is φ = 212112121211166.
The previous prime is 212112121211149. The next prime is 212112121211183. The reversal of 212112121211167 is 761112121211212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212112121211167 - 211 = 212112121209119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212112121251167) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106056060605583 + 106056060605584.
It is an arithmetic number, because the mean of its divisors is an integer number (106056060605584).
Almost surely, 2212112121211167 is an apocalyptic number.
212112121211167 is a deficient number, since it is larger than the sum of its proper divisors (1).
212112121211167 is an equidigital number, since it uses as much as digits as its factorization.
212112121211167 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1344, while the sum is 31.
Adding to 212112121211167 its reverse (761112121211212), we get a palindrome (973224242422379).
The spelling of 212112121211167 in words is "two hundred twelve trillion, one hundred twelve billion, one hundred twenty-one million, two hundred eleven thousand, one hundred sixty-seven".
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