21211302113 has 4 divisors (see below), whose sum is σ = 21270386880. Its totient is φ = 21152217348.

The previous prime is 21211302097. The next prime is 21211302127. The reversal of 21211302113 is 31120311212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21211302113 - 2⁴ = 21211302097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21211302091 and 21211302100.

It is not an unprimeable number, because it can be changed into a prime (21211302173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29541845 + ... + 29542562.

It is an arithmetic number, because the mean of its divisors is an integer number (5317596720).

Almost surely, 2^21211302113 is an apocalyptic number.

It is an amenable number.

21211302113 is a deficient number, since it is larger than the sum of its proper divisors (59084767).

21211302113 is an equidigital number, since it uses as much as digits as its factorization.

21211302113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59084766.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 21211302113 its reverse (31120311212), we get a palindrome (52331613325).

Subtracting 21211302113 from its reverse (31120311212), we obtain a palindrome (9909009099).

The spelling of 21211302113 in words is "twenty-one billion, two hundred eleven million, three hundred two thousand, one hundred thirteen".