Base | Representation |
---|---|
bin | 11110110111011101011… |
… | …000010101100000010111 |
3 | 21111210000101222220100221 |
4 | 132313131120111200113 |
5 | 234223040023134312 |
6 | 4302233550015211 |
7 | 306150440124214 |
oct | 36673530254027 |
9 | 7453011886327 |
10 | 2121133021207 |
11 | 748627324572 |
12 | 2a310b1a7507 |
13 | 1250393c1595 |
14 | 7494048cb0b |
15 | 3a29768d207 |
hex | 1eddd615817 |
2121133021207 has 2 divisors, whose sum is σ = 2121133021208. Its totient is φ = 2121133021206.
The previous prime is 2121133021187. The next prime is 2121133021229. The reversal of 2121133021207 is 7021203311212.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2121133021207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2121133031207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060566510603 + 1060566510604.
It is an arithmetic number, because the mean of its divisors is an integer number (1060566510604).
Almost surely, 22121133021207 is an apocalyptic number.
2121133021207 is a deficient number, since it is larger than the sum of its proper divisors (1).
2121133021207 is an equidigital number, since it uses as much as digits as its factorization.
2121133021207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 2121133021207 its reverse (7021203311212), we get a palindrome (9142336332419).
The spelling of 2121133021207 in words is "two trillion, one hundred twenty-one billion, one hundred thirty-three million, twenty-one thousand, two hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •