Base | Representation |
---|---|
bin | 1100010110001101010… |
… | …1111110100011010111 |
3 | 202021112000101201100211 |
4 | 3011203111332203113 |
5 | 11433410221300002 |
6 | 241240245550251 |
7 | 21216351061432 |
oct | 3054325764327 |
9 | 667460351324 |
10 | 212120103127 |
11 | 81a612a5059 |
12 | 3513a715387 |
13 | 1700631582a |
14 | a3a3a44819 |
15 | 57b751add7 |
hex | 316357e8d7 |
212120103127 has 2 divisors, whose sum is σ = 212120103128. Its totient is φ = 212120103126.
The previous prime is 212120103067. The next prime is 212120103161. The reversal of 212120103127 is 721301021212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212120103127 - 215 = 212120070359 is a prime.
It is a super-3 number, since 3×2121201031273 (a number of 35 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 212120103098 and 212120103107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212120103427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106060051563 + 106060051564.
It is an arithmetic number, because the mean of its divisors is an integer number (106060051564).
Almost surely, 2212120103127 is an apocalyptic number.
212120103127 is a deficient number, since it is larger than the sum of its proper divisors (1).
212120103127 is an equidigital number, since it uses as much as digits as its factorization.
212120103127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 22.
Adding to 212120103127 its reverse (721301021212), we get a palindrome (933421124339).
The spelling of 212120103127 in words is "two hundred twelve billion, one hundred twenty million, one hundred three thousand, one hundred twenty-seven".
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