Base | Representation |
---|---|
bin | 110000001110110000011011… |
… | …110011100010011011110111 |
3 | 1000211001111121012122221222221 |
4 | 300032300123303202123313 |
5 | 210300334344143410241 |
6 | 2031050420432303211 |
7 | 62452121025516133 |
oct | 6016603363423367 |
9 | 1024044535587887 |
10 | 212120311310071 |
11 | 6165179a85111a |
12 | 1b95a4070a1b07 |
13 | 9148b234c3868 |
14 | 3a5496c0243c3 |
15 | 197cb0945a5d1 |
hex | c0ec1bce26f7 |
212120311310071 has 2 divisors, whose sum is σ = 212120311310072. Its totient is φ = 212120311310070.
The previous prime is 212120311309999. The next prime is 212120311310147. The reversal of 212120311310071 is 170013113021212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212120311310071 - 231 = 212118163826423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212120341310071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106060155655035 + 106060155655036.
It is an arithmetic number, because the mean of its divisors is an integer number (106060155655036).
Almost surely, 2212120311310071 is an apocalyptic number.
212120311310071 is a deficient number, since it is larger than the sum of its proper divisors (1).
212120311310071 is an equidigital number, since it uses as much as digits as its factorization.
212120311310071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 212120311310071 its reverse (170013113021212), we get a palindrome (382133424331283).
The spelling of 212120311310071 in words is "two hundred twelve trillion, one hundred twenty billion, three hundred eleven million, three hundred ten thousand, seventy-one".
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