Base | Representation |
---|---|
bin | 110000001110110000011011… |
… | …110011100010011101000011 |
3 | 1000211001111121012122222002202 |
4 | 300032300123303202131003 |
5 | 210300334344143411042 |
6 | 2031050420432303415 |
7 | 62452121025516302 |
oct | 6016603363423503 |
9 | 1024044535588082 |
10 | 212120311310147 |
11 | 6165179a851189 |
12 | 1b95a4070a1b6b |
13 | 9148b234c38c6 |
14 | 3a5496c024439 |
15 | 197cb0945a632 |
hex | c0ec1bce2743 |
212120311310147 has 2 divisors, whose sum is σ = 212120311310148. Its totient is φ = 212120311310146.
The previous prime is 212120311310071. The next prime is 212120311310191. The reversal of 212120311310147 is 741013113021212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212120311310147 - 214 = 212120311293763 is a prime.
It is not a weakly prime, because it can be changed into another prime (212120311315147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106060155655073 + 106060155655074.
It is an arithmetic number, because the mean of its divisors is an integer number (106060155655074).
Almost surely, 2212120311310147 is an apocalyptic number.
212120311310147 is a deficient number, since it is larger than the sum of its proper divisors (1).
212120311310147 is an equidigital number, since it uses as much as digits as its factorization.
212120311310147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 29.
Adding to 212120311310147 its reverse (741013113021212), we get a palindrome (953133424331359).
The spelling of 212120311310147 in words is "two hundred twelve trillion, one hundred twenty billion, three hundred eleven million, three hundred ten thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.098 sec. • engine limits •