Base | Representation |
---|---|
bin | 1001101001010110101000… |
… | …10110100110001110110111 |
3 | 2210002212011111112101100212 |
4 | 10310223110112212032313 |
5 | 10240014400431414312 |
6 | 113040413115500035 |
7 | 4316344614155303 |
oct | 464532426461667 |
9 | 83085144471325 |
10 | 21212111201207 |
11 | 6839007857923 |
12 | 246707115761b |
13 | bab3a7a99294 |
14 | 53495906cd03 |
15 | 26bb97e5a822 |
hex | 134ad45a63b7 |
21212111201207 has 2 divisors, whose sum is σ = 21212111201208. Its totient is φ = 21212111201206.
The previous prime is 21212111201201. The next prime is 21212111201221. The reversal of 21212111201207 is 70210211121212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21212111201207 - 220 = 21212110152631 is a prime.
It is a super-2 number, since 2×212121112012072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21212111201201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10606055600603 + 10606055600604.
It is an arithmetic number, because the mean of its divisors is an integer number (10606055600604).
Almost surely, 221212111201207 is an apocalyptic number.
21212111201207 is a deficient number, since it is larger than the sum of its proper divisors (1).
21212111201207 is an equidigital number, since it uses as much as digits as its factorization.
21212111201207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 21212111201207 its reverse (70210211121212), we get a palindrome (91422322322419).
The spelling of 21212111201207 in words is "twenty-one trillion, two hundred twelve billion, one hundred eleven million, two hundred one thousand, two hundred seven".
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