Base | Representation |
---|---|
bin | 110000001110110100111010… |
… | …000010011100001100100111 |
3 | 1000211001221222212211111210001 |
4 | 300032310322002130030213 |
5 | 210300424213024003310 |
6 | 2031052533140042131 |
7 | 62452351026461161 |
oct | 6016647202341447 |
9 | 1024057885744701 |
10 | 212125113500455 |
11 | 61653834531901 |
12 | 1b95b327393347 |
13 | 914940a38412c |
14 | 3a54ca5b13931 |
15 | 197ccdad3b93a |
hex | c0ed3a09c327 |
212125113500455 has 4 divisors (see below), whose sum is σ = 254550136200552. Its totient is φ = 169700090800360.
The previous prime is 212125113500429. The next prime is 212125113500479. The reversal of 212125113500455 is 554005311521212.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 212125113500455 - 211 = 212125113498407 is a prime.
It is a super-2 number, since 2×2121251135004552 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21212511350041 + ... + 21212511350050.
It is an arithmetic number, because the mean of its divisors is an integer number (63637534050138).
Almost surely, 2212125113500455 is an apocalyptic number.
212125113500455 is a deficient number, since it is larger than the sum of its proper divisors (42425022700097).
212125113500455 is an equidigital number, since it uses as much as digits as its factorization.
212125113500455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42425022700096.
The product of its (nonzero) digits is 60000, while the sum is 37.
The spelling of 212125113500455 in words is "two hundred twelve trillion, one hundred twenty-five billion, one hundred thirteen million, five hundred thousand, four hundred fifty-five".
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