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212125433 = 13127128483
BaseRepresentation
bin11001010010011…
…00011011111001
3112210011002101112
430221030123321
5413301003213
633014330105
75154015332
oct1451143371
9483132345
10212125433
11a9814a83
125b059935
1334c41410
142025b289
1513951ea8
hexca4c6f9

212125433 has 8 divisors (see below), whose sum is σ = 230243328. Its totient is φ = 194264784.

The previous prime is 212125427. The next prime is 212125483. The reversal of 212125433 is 334521212.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212125433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 212125399 and 212125408.

It is not an unprimeable number, because it can be changed into a prime (212125423) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62591 + ... + 65892.

It is an arithmetic number, because the mean of its divisors is an integer number (28780416).

Almost surely, 2212125433 is an apocalyptic number.

It is an amenable number.

212125433 is a deficient number, since it is larger than the sum of its proper divisors (18117895).

212125433 is a wasteful number, since it uses less digits than its factorization.

212125433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 128623.

The product of its digits is 1440, while the sum is 23.

The square root of 212125433 is about 14564.5265285213. The cubic root of 212125433 is about 596.3907706013.

Adding to 212125433 its reverse (334521212), we get a palindrome (546646645).

The spelling of 212125433 in words is "two hundred twelve million, one hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 13 127 1651 128483 1670279 16317341 212125433