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21213113333 = 51674105499
BaseRepresentation
bin10011110000011001…
…100110101111110101
32000202101012210220012
4103300121212233311
5321421024111313
613424542350005
71350452326316
oct236031465765
960671183805
1021213113333
118aa6282025
12414028b305
132000b10a89
14105346a60d
158424e6da8
hex4f0666bf5

21213113333 has 4 divisors (see below), whose sum is σ = 21217224000. Its totient is φ = 21209002668.

The previous prime is 21213113321. The next prime is 21213113347. The reversal of 21213113333 is 33331131212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21213113333 - 212 = 21213109237 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21213113299 and 21213113308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21213110333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2047583 + ... + 2057916.

It is an arithmetic number, because the mean of its divisors is an integer number (5304306000).

Almost surely, 221213113333 is an apocalyptic number.

It is an amenable number.

21213113333 is a deficient number, since it is larger than the sum of its proper divisors (4110667).

21213113333 is an equidigital number, since it uses as much as digits as its factorization.

21213113333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4110666.

The product of its digits is 972, while the sum is 23.

Adding to 21213113333 its reverse (33331131212), we get a palindrome (54544244545).

The spelling of 21213113333 in words is "twenty-one billion, two hundred thirteen million, one hundred thirteen thousand, three hundred thirty-three".

Divisors: 1 5167 4105499 21213113333