Base | Representation |
---|---|
bin | 10011110000011010… |
… | …010110110011100001 |
3 | 2000202101120210220201 |
4 | 103300122112303201 |
5 | 321421101411202 |
6 | 13424550505201 |
7 | 1350454106233 |
oct | 236032266341 |
9 | 60671523821 |
10 | 21213310177 |
11 | 8aa63a6a04 |
12 | 4140365201 |
13 | 2000b7c557 |
14 | 10534bc253 |
15 | 842535387 |
hex | 4f0696ce1 |
21213310177 has 2 divisors, whose sum is σ = 21213310178. Its totient is φ = 21213310176.
The previous prime is 21213310061. The next prime is 21213310187. The reversal of 21213310177 is 77101331212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20202642496 + 1010667681 = 142136^2 + 31791^2 .
It is a cyclic number.
It is not a de Polignac number, because 21213310177 - 215 = 21213277409 is a prime.
It is a super-2 number, since 2×212133101772 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21213310187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10606655088 + 10606655089.
It is an arithmetic number, because the mean of its divisors is an integer number (10606655089).
Almost surely, 221213310177 is an apocalyptic number.
It is an amenable number.
21213310177 is a deficient number, since it is larger than the sum of its proper divisors (1).
21213310177 is an equidigital number, since it uses as much as digits as its factorization.
21213310177 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1764, while the sum is 28.
Adding to 21213310177 its reverse (77101331212), we get a palindrome (98314641389).
The spelling of 21213310177 in words is "twenty-one billion, two hundred thirteen million, three hundred ten thousand, one hundred seventy-seven".
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