Base | Representation |
---|---|
bin | 111111001110000… |
… | …1111001000001100 |
3 | 12110211122210100200 |
4 | 1332130033020030 |
5 | 13321030044322 |
6 | 550255253500 |
7 | 103366006050 |
oct | 17634171014 |
9 | 5424583320 |
10 | 2121331212 |
11 | 9994885a0 |
12 | 4b251a290 |
13 | 27a649190 |
14 | 161a3dc60 |
15 | c637c8ac |
hex | 7e70f20c |
2121331212 has 432 divisors, whose sum is σ = 7571596032. Its totient is φ = 483356160.
The previous prime is 2121331207. The next prime is 2121331241.
2121331212 is a `hidden beast` number, since 2 + 121 + 331 + 212 = 666.
2121331212 is nontrivially palindromic in base 10.
It is a super-2 number, since 2×21213312122 = 9000092222010777888, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a nude number because it is divisible by every one of its digits.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 49333263 + ... + 49333305.
Almost surely, 22121331212 is an apocalyptic number.
2121331212 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 2121331212, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3785798016).
2121331212 is an abundant number, since it is smaller than the sum of its proper divisors (5450264820).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2121331212 is a wasteful number, since it uses less digits than its factorization.
2121331212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 158 (or 116 counting only the distinct ones).
The product of its digits is 144, while the sum is 18.
The square root of 2121331212 is about 46057.9115028026. The cubic root of 2121331212 is about 1284.9004877846.
It can be divided in two parts, 21213 and 31212, that added together give a palindrome (52425).
The spelling of 2121331212 in words is "two billion, one hundred twenty-one million, three hundred thirty-one thousand, two hundred twelve".
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