Base | Representation |
---|---|
bin | 11110110111101101011… |
… | …110100111000011110111 |
3 | 21111210201020012101210012 |
4 | 132313231132213003313 |
5 | 234224113143221211 |
6 | 4302320434450435 |
7 | 306160226561135 |
oct | 36675536470367 |
9 | 7453636171705 |
10 | 2121403101431 |
11 | 748755822869 |
12 | 2a3185733a1b |
13 | 125080344a73 |
14 | 749682b4755 |
15 | 3a2b123bd8b |
hex | 1eded7a70f7 |
2121403101431 has 2 divisors, whose sum is σ = 2121403101432. Its totient is φ = 2121403101430.
The previous prime is 2121403101397. The next prime is 2121403101443. The reversal of 2121403101431 is 1341013041212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2121403101431 - 230 = 2120329359607 is a prime.
It is a super-2 number, since 2×21214031014312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2121403101397 and 2121403101406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2121403101451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060701550715 + 1060701550716.
It is an arithmetic number, because the mean of its divisors is an integer number (1060701550716).
Almost surely, 22121403101431 is an apocalyptic number.
2121403101431 is a deficient number, since it is larger than the sum of its proper divisors (1).
2121403101431 is an equidigital number, since it uses as much as digits as its factorization.
2121403101431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 2121403101431 its reverse (1341013041212), we get a palindrome (3462416142643).
The spelling of 2121403101431 in words is "two trillion, one hundred twenty-one billion, four hundred three million, one hundred one thousand, four hundred thirty-one".
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