Base | Representation |
---|---|
bin | 1001101001011010001110… |
… | …00111000010101101101011 |
3 | 2210010001010200022212110121 |
4 | 10310231013013002231223 |
5 | 10240032321321102103 |
6 | 113041332133424111 |
7 | 4316443413026242 |
oct | 464550707025553 |
9 | 83101120285417 |
10 | 21214036503403 |
11 | 6839905614967 |
12 | 2467509a9b037 |
13 | bab62391b753 |
14 | 534a9ca41959 |
15 | 26bc5beb56bd |
hex | 134b471c2b6b |
21214036503403 has 2 divisors, whose sum is σ = 21214036503404. Its totient is φ = 21214036503402.
The previous prime is 21214036503397. The next prime is 21214036503419. The reversal of 21214036503403 is 30430563041212.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21214036503403 - 221 = 21214034406251 is a prime.
It is not a weakly prime, because it can be changed into another prime (21214036503493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10607018251701 + 10607018251702.
It is an arithmetic number, because the mean of its divisors is an integer number (10607018251702).
Almost surely, 221214036503403 is an apocalyptic number.
21214036503403 is a deficient number, since it is larger than the sum of its proper divisors (1).
21214036503403 is an equidigital number, since it uses as much as digits as its factorization.
21214036503403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 21214036503403 its reverse (30430563041212), we get a palindrome (51644599544615).
The spelling of 21214036503403 in words is "twenty-one trillion, two hundred fourteen billion, thirty-six million, five hundred three thousand, four hundred three".
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