Base | Representation |
---|---|
bin | 11110111000011110001… |
… | …011010000100001110011 |
3 | 21111212211011112211120102 |
4 | 132320132023100201303 |
5 | 234232301322040422 |
6 | 4302533502103015 |
7 | 306216410213123 |
oct | 36703613204163 |
9 | 7455734484512 |
10 | 2122220111987 |
11 | 749034a219a8 |
12 | 2a337327aa6b |
13 | 1251806a2471 |
14 | 74a049cac83 |
15 | 3a30cd24192 |
hex | 1ee1e2d0873 |
2122220111987 has 2 divisors, whose sum is σ = 2122220111988. Its totient is φ = 2122220111986.
The previous prime is 2122220111983. The next prime is 2122220111989. The reversal of 2122220111987 is 7891110222212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2122220111987 - 22 = 2122220111983 is a prime.
It is a super-2 number, since 2×21222201119872 (a number of 25 digits) contains 22 as substring.
Together with 2122220111989, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2122220111987.
It is not a weakly prime, because it can be changed into another prime (2122220111983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061110055993 + 1061110055994.
It is an arithmetic number, because the mean of its divisors is an integer number (1061110055994).
Almost surely, 22122220111987 is an apocalyptic number.
2122220111987 is a deficient number, since it is larger than the sum of its proper divisors (1).
2122220111987 is an equidigital number, since it uses as much as digits as its factorization.
2122220111987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 38.
The spelling of 2122220111987 in words is "two trillion, one hundred twenty-two billion, two hundred twenty million, one hundred eleven thousand, nine hundred eighty-seven".
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