Base | Representation |
---|---|
bin | 1100010110100111100… |
… | …1100101100001111001 |
3 | 202021210200101012020022 |
4 | 3011221321211201321 |
5 | 11434121401213423 |
6 | 241255215340225 |
7 | 21222155044322 |
oct | 3055171454171 |
9 | 667720335208 |
10 | 212230101113 |
11 | 820083a5188 |
12 | 3516b521675 |
13 | 17023049cb4 |
14 | a3b44b9449 |
15 | 57c1ee7dc8 |
hex | 3169e65879 |
212230101113 has 4 divisors (see below), whose sum is σ = 212246706048. Its totient is φ = 212213496180.
The previous prime is 212230101091. The next prime is 212230101131. The reversal of 212230101113 is 311101032212.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 212230101113 - 230 = 211156359289 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 212230101091 and 212230101100.
It is not an unprimeable number, because it can be changed into a prime (212230101173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8283281 + ... + 8308862.
It is an arithmetic number, because the mean of its divisors is an integer number (53061676512).
Almost surely, 2212230101113 is an apocalyptic number.
It is an amenable number.
212230101113 is a deficient number, since it is larger than the sum of its proper divisors (16604935).
212230101113 is a wasteful number, since it uses less digits than its factorization.
212230101113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16604934.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 212230101113 its reverse (311101032212), we get a palindrome (523331133325).
The spelling of 212230101113 in words is "two hundred twelve billion, two hundred thirty million, one hundred one thousand, one hundred thirteen".
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