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2122312132117 is a prime number
BaseRepresentation
bin11110111000100011101…
…010010010011000010101
321111220001120200221110101
4132320203222102120111
5234232443401211432
64302550550254101
7306221605321312
oct36704352223025
97456046627411
102122312132117
11749081962aa1
122a339a057331
13125196780a48
1474a12d01d09
153a315e4e4e7
hex1ee23a92615

2122312132117 has 2 divisors, whose sum is σ = 2122312132118. Its totient is φ = 2122312132116.

The previous prime is 2122312132079. The next prime is 2122312132223. The reversal of 2122312132117 is 7112312132212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1509263847441 + 613048284676 = 1228521^2 + 782974^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2122312132117 is a prime.

It is a super-2 number, since 2×21223121321172 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2122312142117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061156066058 + 1061156066059.

It is an arithmetic number, because the mean of its divisors is an integer number (1061156066059).

Almost surely, 22122312132117 is an apocalyptic number.

It is an amenable number.

2122312132117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2122312132117 is an equidigital number, since it uses as much as digits as its factorization.

2122312132117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2016, while the sum is 28.

Adding to 2122312132117 its reverse (7112312132212), we get a palindrome (9234624264329).

The spelling of 2122312132117 in words is "two trillion, one hundred twenty-two billion, three hundred twelve million, one hundred thirty-two thousand, one hundred seventeen".