Base | Representation |
---|---|
bin | 11110111001001100110… |
… | …011100010110001001111 |
3 | 21111221211200121102110012 |
4 | 132321030303202301033 |
5 | 234240402110040044 |
6 | 4303143245503435 |
7 | 306244656601253 |
oct | 36711463426117 |
9 | 7457750542405 |
10 | 2123002424399 |
11 | 7493a658188a |
12 | 2a3551271b7b |
13 | 1252767a160c |
14 | 74a7a870263 |
15 | 3a35685559e |
hex | 1ee4cce2c4f |
2123002424399 has 2 divisors, whose sum is σ = 2123002424400. Its totient is φ = 2123002424398.
The previous prime is 2123002424393. The next prime is 2123002424419. The reversal of 2123002424399 is 9934242003212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2123002424399 - 216 = 2123002358863 is a prime.
It is a super-2 number, since 2×21230024243992 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2123002424393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061501212199 + 1061501212200.
It is an arithmetic number, because the mean of its divisors is an integer number (1061501212200).
Almost surely, 22123002424399 is an apocalyptic number.
2123002424399 is a deficient number, since it is larger than the sum of its proper divisors (1).
2123002424399 is an equidigital number, since it uses as much as digits as its factorization.
2123002424399 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 186624, while the sum is 41.
The spelling of 2123002424399 in words is "two trillion, one hundred twenty-three billion, two million, four hundred twenty-four thousand, three hundred ninety-nine".
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