Base | Representation |
---|---|
bin | 11110111001001110100… |
… | …001110100000101001111 |
3 | 21111221220201000001001122 |
4 | 132321032201310011033 |
5 | 234240432010044101 |
6 | 4303150201231155 |
7 | 306245460364433 |
oct | 36711641640517 |
9 | 7457821001048 |
10 | 2123031331151 |
11 | 749410925965 |
12 | 2a355aa924bb |
13 | 12527c782ac3 |
14 | 74a806369c3 |
15 | 3a35916551b |
hex | 1ee4e87414f |
2123031331151 has 2 divisors, whose sum is σ = 2123031331152. Its totient is φ = 2123031331150.
The previous prime is 2123031331087. The next prime is 2123031331153. The reversal of 2123031331151 is 1511331303212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2123031331151 - 26 = 2123031331087 is a prime.
Together with 2123031331153, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2123031331151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2123031331153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061515665575 + 1061515665576.
It is an arithmetic number, because the mean of its divisors is an integer number (1061515665576).
Almost surely, 22123031331151 is an apocalyptic number.
2123031331151 is a deficient number, since it is larger than the sum of its proper divisors (1).
2123031331151 is an equidigital number, since it uses as much as digits as its factorization.
2123031331151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 26.
Adding to 2123031331151 its reverse (1511331303212), we get a palindrome (3634362634363).
The spelling of 2123031331151 in words is "two trillion, one hundred twenty-three billion, thirty-one million, three hundred thirty-one thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •