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21230431133 = 87511242603
BaseRepresentation
bin10011110001011011…
…101010101110011101
32000210120210122110012
4103301123222232131
5321434442244013
613430401453005
71351052454452
oct236133525635
960716718405
1021230431133
11900503015a
124146041165
1320045953b2
141055897829
15843cb81a8
hex4f16eab9d

21230431133 has 4 divisors (see below), whose sum is σ = 21230761248. Its totient is φ = 21230101020.

The previous prime is 21230431097. The next prime is 21230431153. The reversal of 21230431133 is 33113403212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21230431133 - 214 = 21230414749 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21230431099 and 21230431108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21230431153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33791 + ... + 208812.

It is an arithmetic number, because the mean of its divisors is an integer number (5307690312).

Almost surely, 221230431133 is an apocalyptic number.

It is an amenable number.

21230431133 is a deficient number, since it is larger than the sum of its proper divisors (330115).

21230431133 is an equidigital number, since it uses as much as digits as its factorization.

21230431133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 330114.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 21230431133 its reverse (33113403212), we get a palindrome (54343834345).

The spelling of 21230431133 in words is "twenty-one billion, two hundred thirty million, four hundred thirty-one thousand, one hundred thirty-three".

Divisors: 1 87511 242603 21230431133