Base | Representation |
---|---|
bin | 1100010110111010111… |
… | …0001111011011111111 |
3 | 202022000022121221122021 |
4 | 3011232232033123333 |
5 | 11434303104404434 |
6 | 241311225501011 |
7 | 21224156556352 |
oct | 3055656173377 |
9 | 668008557567 |
10 | 212311013119 |
11 | 8204a039607 |
12 | 35192641767 |
13 | 17036a3951a |
14 | a3c113c299 |
15 | 57c917bcb4 |
hex | 316eb8f6ff |
212311013119 has 2 divisors, whose sum is σ = 212311013120. Its totient is φ = 212311013118.
The previous prime is 212311013081. The next prime is 212311013143. The reversal of 212311013119 is 911310113212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212311013119 is a prime.
It is a super-2 number, since 2×2123110131192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 212311013093 and 212311013102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212311013149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106155506559 + 106155506560.
It is an arithmetic number, because the mean of its divisors is an integer number (106155506560).
Almost surely, 2212311013119 is an apocalyptic number.
212311013119 is a deficient number, since it is larger than the sum of its proper divisors (1).
212311013119 is an equidigital number, since it uses as much as digits as its factorization.
212311013119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 25.
The spelling of 212311013119 in words is "two hundred twelve billion, three hundred eleven million, thirteen thousand, one hundred nineteen".
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