Base | Representation |
---|---|
bin | 10011110001011111… |
… | …010111100101110101 |
3 | 2000210122121221022112 |
4 | 103301133113211311 |
5 | 321440214320313 |
6 | 13430434340405 |
7 | 1351063635152 |
oct | 236137274565 |
9 | 60718557275 |
10 | 21231401333 |
11 | 900563307a |
12 | 414642a705 |
13 | 2004844b8c |
14 | 1055a6b229 |
15 | 843e0a8a8 |
hex | 4f17d7975 |
21231401333 has 2 divisors, whose sum is σ = 21231401334. Its totient is φ = 21231401332.
The previous prime is 21231401311. The next prime is 21231401377. The reversal of 21231401333 is 33310413212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19853655409 + 1377745924 = 140903^2 + 37118^2 .
It is a cyclic number.
It is not a de Polignac number, because 21231401333 - 220 = 21230352757 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21231401299 and 21231401308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21231401393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10615700666 + 10615700667.
It is an arithmetic number, because the mean of its divisors is an integer number (10615700667).
Almost surely, 221231401333 is an apocalyptic number.
It is an amenable number.
21231401333 is a deficient number, since it is larger than the sum of its proper divisors (1).
21231401333 is an equidigital number, since it uses as much as digits as its factorization.
21231401333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 21231401333 its reverse (33310413212), we get a palindrome (54541814545).
The spelling of 21231401333 in words is "twenty-one billion, two hundred thirty-one million, four hundred one thousand, three hundred thirty-three".
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