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212411220013 is a prime number
BaseRepresentation
bin1100010111010010110…
…0100000000000101101
3202022021022011222122201
43011310230200000231
511440004233020023
6241325205341501
721226514402626
oct3056454400055
9668238158581
10212411220013
11820a0661523
1235200107891
1317051723245
14a3d0584a4d
1557d2d72bad
hex3174b2002d

212411220013 has 2 divisors, whose sum is σ = 212411220014. Its totient is φ = 212411220012.

The previous prime is 212411220011. The next prime is 212411220017. The reversal of 212411220013 is 310022114212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 133065907524 + 79345312489 = 364782^2 + 281683^2 .

It is a cyclic number.

It is not a de Polignac number, because 212411220013 - 21 = 212411220011 is a prime.

It is a super-2 number, since 2×2124112200132 (a number of 23 digits) contains 22 as substring.

Together with 212411220011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212411220011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106205610006 + 106205610007.

It is an arithmetic number, because the mean of its divisors is an integer number (106205610007).

Almost surely, 2212411220013 is an apocalyptic number.

It is an amenable number.

212411220013 is a deficient number, since it is larger than the sum of its proper divisors (1).

212411220013 is an equidigital number, since it uses as much as digits as its factorization.

212411220013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 212411220013 its reverse (310022114212), we get a palindrome (522433334225).

The spelling of 212411220013 in words is "two hundred twelve billion, four hundred eleven million, two hundred twenty thousand, thirteen".