Base | Representation |
---|---|
bin | 1100010111010010110… |
… | …0111111110111011101 |
3 | 202022021022102121122022 |
4 | 3011310230333313131 |
5 | 11440004301203433 |
6 | 241325212225525 |
7 | 21226515455216 |
oct | 3056454776735 |
9 | 668238377568 |
10 | 212411350493 |
11 | 820a0740561 |
12 | 3520016b2a5 |
13 | 1705176a754 |
14 | a3d05ba40d |
15 | 57d2d9b698 |
hex | 3174b3fddd |
212411350493 has 2 divisors, whose sum is σ = 212411350494. Its totient is φ = 212411350492.
The previous prime is 212411350477. The next prime is 212411350511. The reversal of 212411350493 is 394053114212.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 138177988729 + 74233361764 = 371723^2 + 272458^2 .
It is a cyclic number.
It is not a de Polignac number, because 212411350493 - 24 = 212411350477 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212411350693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106205675246 + 106205675247.
It is an arithmetic number, because the mean of its divisors is an integer number (106205675247).
Almost surely, 2212411350493 is an apocalyptic number.
It is an amenable number.
212411350493 is a deficient number, since it is larger than the sum of its proper divisors (1).
212411350493 is an equidigital number, since it uses as much as digits as its factorization.
212411350493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 212411350493 in words is "two hundred twelve billion, four hundred eleven million, three hundred fifty thousand, four hundred ninety-three".
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