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212411442433 is a prime number
BaseRepresentation
bin1100010111010010110…
…1010110010100000001
3202022021022121021202111
43011310231112110001
511440004312124213
6241325214215321
721226516320241
oct3056455262401
9668238537674
10212411442433
11820a07a3643
12352001b4541
13170517a0558
14a3d0601b21
1557d2db8a3d
hex3174b56501

212411442433 has 2 divisors, whose sum is σ = 212411442434. Its totient is φ = 212411442432.

The previous prime is 212411442409. The next prime is 212411442497. The reversal of 212411442433 is 334244114212.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 195711566449 + 16699875984 = 442393^2 + 129228^2 .

It is a cyclic number.

It is not a de Polignac number, because 212411442433 - 229 = 211874571521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 212411442395 and 212411442404.

It is not a weakly prime, because it can be changed into another prime (212411440433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106205721216 + 106205721217.

It is an arithmetic number, because the mean of its divisors is an integer number (106205721217).

Almost surely, 2212411442433 is an apocalyptic number.

It is an amenable number.

212411442433 is a deficient number, since it is larger than the sum of its proper divisors (1).

212411442433 is an equidigital number, since it uses as much as digits as its factorization.

212411442433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 18432, while the sum is 31.

Adding to 212411442433 its reverse (334244114212), we get a palindrome (546655556645).

The spelling of 212411442433 in words is "two hundred twelve billion, four hundred eleven million, four hundred forty-two thousand, four hundred thirty-three".