Base | Representation |
---|---|
bin | 11110111010010100010… |
… | …000111011101111111111 |
3 | 21112001221020112012000012 |
4 | 132322110100323233333 |
5 | 234300331013424411 |
6 | 4303502234053435 |
7 | 306316455142166 |
oct | 36722420735777 |
9 | 7461836465005 |
10 | 2124201311231 |
11 | 74996129824a |
12 | 2a382687a27b |
13 | 125407c961cc |
14 | 74b51b903dd |
15 | 3a3c6c2118b |
hex | 1ee9443bbff |
2124201311231 has 2 divisors, whose sum is σ = 2124201311232. Its totient is φ = 2124201311230.
The previous prime is 2124201311201. The next prime is 2124201311249. The reversal of 2124201311231 is 1321131024212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2124201311231 - 214 = 2124201294847 is a prime.
It is a super-2 number, since 2×21242013112312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2124201311197 and 2124201311206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2124201311201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1062100655615 + 1062100655616.
It is an arithmetic number, because the mean of its divisors is an integer number (1062100655616).
Almost surely, 22124201311231 is an apocalyptic number.
2124201311231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2124201311231 is an equidigital number, since it uses as much as digits as its factorization.
2124201311231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 2124201311231 its reverse (1321131024212), we get a palindrome (3445332335443).
The spelling of 2124201311231 in words is "two trillion, one hundred twenty-four billion, two hundred one million, three hundred eleven thousand, two hundred thirty-one".
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