Base | Representation |
---|---|
bin | 11110111011001011000… |
… | …110011100111011001111 |
3 | 21112011022100122222122001 |
4 | 132323023012130323033 |
5 | 234304222023413130 |
6 | 4304133420533131 |
7 | 306351326044435 |
oct | 36731306347317 |
9 | 7464270588561 |
10 | 2125121310415 |
11 | 74a29363a254 |
12 | 2a3a429b11a7 |
13 | 12552377281c |
14 | 74bdc034d55 |
15 | 3a42c89d6ca |
hex | 1eecb19cecf |
2125121310415 has 8 divisors (see below), whose sum is σ = 2564234775648. Its totient is φ = 1690704246240.
The previous prime is 2125121310407. The next prime is 2125121310439. The reversal of 2125121310415 is 5140131215212.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2125121310415 - 23 = 2125121310407 is a prime.
It is a super-2 number, since 2×21251213104152 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1174099267 + ... + 1174101076.
It is an arithmetic number, because the mean of its divisors is an integer number (320529346956).
Almost surely, 22125121310415 is an apocalyptic number.
2125121310415 is a deficient number, since it is larger than the sum of its proper divisors (439113465233).
2125121310415 is a wasteful number, since it uses less digits than its factorization.
2125121310415 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2348200529.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 2125121310415 its reverse (5140131215212), we get a palindrome (7265252525627).
The spelling of 2125121310415 in words is "two trillion, one hundred twenty-five billion, one hundred twenty-one million, three hundred ten thousand, four hundred fifteen".
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