Base | Representation |
---|---|
bin | 11110111100111000001… |
… | …000000011100101111011 |
3 | 21112100000211111202222101 |
4 | 132330320020003211323 |
5 | 234321443303304413 |
6 | 4305035121404231 |
7 | 306444546334531 |
oct | 36747010034573 |
9 | 7470024452871 |
10 | 2126950447483 |
11 | 750042094a84 |
12 | 2a4273499677 |
13 | 1257556c4b54 |
14 | 74d32d34151 |
15 | 3a4d825eedd |
hex | 1ef3820397b |
2126950447483 has 2 divisors, whose sum is σ = 2126950447484. Its totient is φ = 2126950447482.
The previous prime is 2126950447477. The next prime is 2126950447537. The reversal of 2126950447483 is 3847440596212.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2126950447483 is a prime.
It is not a weakly prime, because it can be changed into another prime (2126950487483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1063475223741 + 1063475223742.
It is an arithmetic number, because the mean of its divisors is an integer number (1063475223742).
It is a 1-persistent number, because it is pandigital, but 2⋅2126950447483 = 4253900894966 is not.
Almost surely, 22126950447483 is an apocalyptic number.
2126950447483 is a deficient number, since it is larger than the sum of its proper divisors (1).
2126950447483 is an equidigital number, since it uses as much as digits as its factorization.
2126950447483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11612160, while the sum is 55.
The spelling of 2126950447483 in words is "two trillion, one hundred twenty-six billion, nine hundred fifty million, four hundred forty-seven thousand, four hundred eighty-three".
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