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2126950447477 is a prime number
BaseRepresentation
bin11110111100111000001…
…000000011100101110101
321112100000211111202222011
4132330320020003211311
5234321443303304402
64305035121404221
7306444546334522
oct36747010034565
97470024452864
102126950447477
11750042094a79
122a4273499671
131257556c4b4b
1474d32d34149
153a4d825eed7
hex1ef38203975

2126950447477 has 2 divisors, whose sum is σ = 2126950447478. Its totient is φ = 2126950447476.

The previous prime is 2126950447471. The next prime is 2126950447483. The reversal of 2126950447477 is 7747440596212.

It is a balanced prime because it is at equal distance from previous prime (2126950447471) and next prime (2126950447483).

It can be written as a sum of positive squares in only one way, i.e., 1091859896241 + 1035090551236 = 1044921^2 + 1017394^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2126950447477 is a prime.

It is a super-2 number, since 2×21269504474772 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2126950447471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1063475223738 + 1063475223739.

It is an arithmetic number, because the mean of its divisors is an integer number (1063475223739).

Almost surely, 22126950447477 is an apocalyptic number.

It is an amenable number.

2126950447477 is a deficient number, since it is larger than the sum of its proper divisors (1).

2126950447477 is an equidigital number, since it uses as much as digits as its factorization.

2126950447477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23708160, while the sum is 58.

The spelling of 2126950447477 in words is "two trillion, one hundred twenty-six billion, nine hundred fifty million, four hundred forty-seven thousand, four hundred seventy-seven".